A bag contains 3 red balls and 2 blue balls. If one ball is drawn, what is the probability of red?

A bag contains 3 red balls and 2 blue balls. If one ball is drawn, what is the probability of red?

• A. 3/5
• B. 2/5
• C. 1/2
• D. 4/5

Answer: (A)

When each ball in the bag is equally likely to be drawn, the probability of getting red is the number of red balls divided by the total number of balls. There are three red balls and five balls in total, so the chance of red is three out of five. That directly matches the actual composition: three red, two blue. The other options would imply different counts: two out of five would correspond to drawing blue, one half would imply an equal split between red and blue that doesn’t match the bag, and four out of five would require four red balls in the bag. Since the bag has three red and two blue, three out of five is the correct probability.

When each ball in the bag is equally likely to be drawn, the probability of getting red is the number of red balls divided by the total number of balls. There are three red balls and five balls in total, so the chance of red is three out of five. That directly matches the actual composition: three red, two blue.

The other options would imply different counts: two out of five would correspond to drawing blue, one half would imply an equal split between red and blue that doesn’t match the bag, and four out of five would require four red balls in the bag. Since the bag has three red and two blue, three out of five is the correct probability.